How much solar energy (kJ) would have to be transferred to a 186.0 foot length of asphalt?


Question:
highway that is 46.0 feet wide and 24.6 centimeters deep in order to raise the temperature 2.50 oC ?



The average density of asphalt is 721 kg/m3



The specific heat of asphalt is 0.920 kJ/kg-oC

Answer:
1) Calculate the mass of asphalt in SI units
The total volume is 186 x 0.3048 x 46 x 0.3048 x 0.246 = 195.5 m^3.
The total mass is 195.5 m^3 x 721 kg/m3 = 141 x 10^3 kg.

2) Amount of energy to raise the temperature by 2.5 degree C= Mass of asphalt * specific heat of asphalt * temperature rise
141 x 10^3 kg * 0.920 kJ/kg C * 2.5 C = 324000 kJ
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