In a scale model of our solar system, if a half-inch marble represents earth, how far away would mars be?
Question:
b. 100 yards
c. 100 miles
d. 100 feet
pls give proof why you chose that letter..ty!^^.
Answer:
This sounds like homework, so I am going to direct you to a site that can help you.
Remember that the answer depends on where mars is right now, it moves!
B---100 yards----chosen because i calculate this by envisioning the size the sun would need to be (about as big as the kitchen I'm sitting in)--and depicting how far it would need to be to have the same apparent diameter as the actual sun.
Before the choices, I roughly guessed Mars would be an eighth-mile away.
The earth is about 8000 miles across, so you are setting up a scale where 8000=1/2 inch. The closest that Mars gets to us is about 40 million miles, which is about 5000 times the diameter of the earth. This would be about 2500 inches in your model. This comes out to be between b and d. Of course, the farthest that Mars is away from us is about 230 million miles, which is about 30,000 times the diameter of the earth, which corresponds to 15,000 inches, which is between b and c.
None of the above. The distance between Mars and Earth is constantly changing as they travel in their orbits around the Sun. Here are the results for the cases where they are both on a line on the same side of the Sun (min distance) and both on a line on opposite sides of the Sun (max distance)
Earth Avg Dia (km)12756
Earth Avg Dist from sun (km)149,597,890
Mars Avg Dist from sun (km)227,936,640
Min dist (km)78,338,750
Max dist (km)377,534,530
Distance scale factor (inches/km)0.000039197241
(0.5 inch/12756 km)
Min dist
---------------
3071 inches
255.9 feet
85.3 yards
0.048 miles
Max dist
------------------
14798 inches
1233.2 feet
411.1 yards
0.234 miles
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